(6x^2-12)/(3x-4)=2x

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Solution for (6x^2-12)/(3x-4)=2x equation: 


D( x )

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0 // + 4

3*x = 4 // : 3

x = 4/3

x in (-oo:4/3) U (4/3:+oo)

(6*x^2-12)/(3*x-4) = 2*x // - 2*x

(6*x^2-12)/(3*x-4)-(2*x) = 0

(6*x^2-12)/(3*x-4)-2*x = 0

(6*x^2-12)/(3*x-4)+(-2*x*(3*x-4))/(3*x-4) = 0

6*x^2-2*x*(3*x-4)-12 = 0

8*x-12 = 0

(8*x-12)/(3*x-4) = 0

(8*x-12)/(3*x-4) = 0 // * 3*x-4

8*x-12 = 0

8*x-12 = 0 // + 12

8*x = 12 // : 8

x = 12/8

x = 3/2

x = 3/2

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